2n^2-450=0

Solution for 2n^2-450=0 equation:

2n^2-450=0

a = 2; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·2·(-450)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*2}=\frac{-60}{4}
=-15
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*2}=\frac{60}{4}
=15
$